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Re: explaining i/q

From: David Hagood
Subject: Re: explaining i/q
Date: Wed, 4 Nov 2020 19:13:09 -0600
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:78.0) Gecko/20100101 Thunderbird/78.3.2

On 11/4/20 6:26 PM, david vanhorn wrote:
"Twice the bandwidth" but that doesn't account for the 0 Hz "hole" where the incoming signal is exactly at the sampling rate.
Or am I missing something?

What "hole" are you referring to? There is the "zero bang", which occurs because most systems aren't perfect and have a DC component to the LOs and mixing system, but a "perfect" system with zero DC in the LOs will resolve a DC signal. The imperfection of the implementation doesn't mean the concept is imperfect.

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