Re: How should tupletSpannerDuration actually work?

[Hans Åberg]

On 12 Jan 2013, at 12:53, David Kastrup <address@hidden> wrote:

> "Phil Holmes" <address@hidden> writes:
> 
>>> I have a hard time considering the output of
>> 
>>> \version "2.16.0"
>>> 
>>> \relative c' {
>>> \set tupletSpannerDuration = #(ly:make-moment 1 2)
>>> \times 2/3 { c8 d e f g a g f e d c d }
>>> \set tupletSpannerDuration = #(ly:make-moment 1 4)
>>> \times 2/3 { c4 d e f g a g f e d c d }
>>> }
>>> 
>>> 
>>> useful:
>> 
>> I think that looks OK?
> 
> No.  In the first case, the beaming should be 2+2+2 rather than 3+3: the
> whole point is that there is supposed to be a subdivision into three,
> and 3+3 defeats that.

Hindemith, "Elementary training", p. 116, gives the rule that triplets are 
tripartite and sextuplet bipartite. Septuplets are "in one", beamed together as 
though there are no subaccents. Those are defaults. Users may want to have 
other beamings.

Hans