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Re: How should tupletSpannerDuration actually work?
From: |
Hans Aberg |
Subject: |
Re: How should tupletSpannerDuration actually work? |
Date: |
Sun, 13 Jan 2013 14:45:55 +0100 |
On 12 Jan 2013, at 12:53, David Kastrup <address@hidden> wrote:
> "Phil Holmes" <address@hidden> writes:
>
>>> I have a hard time considering the output of
>>
>>> \version "2.16.0"
>>>
>>> \relative c' {
>>> \set tupletSpannerDuration = #(ly:make-moment 1 2)
>>> \times 2/3 { c8 d e f g a g f e d c d }
>>> \set tupletSpannerDuration = #(ly:make-moment 1 4)
>>> \times 2/3 { c4 d e f g a g f e d c d }
>>> }
>>>
>>>
>>> useful:
>>
>> I think that looks OK?
>
> No. In the first case, the beaming should be 2+2+2 rather than 3+3: the
> whole point is that there is supposed to be a subdivision into three,
> and 3+3 defeats that.
Hindemith, "Elementary training", p. 116, gives the rule that triplets are
tripartite and sextuplet bipartite. Septuplets are "in one", beamed together as
though there are no subaccents. Those are defaults. Users may want to have
other beamings.
Hans
Re: How should tupletSpannerDuration actually work?, Keith OHara, 2013/01/12