Re: How should tupletSpannerDuration actually work?

[David Kastrup]

Hans Åberg <address@hidden> writes:

> On 12 Jan 2013, at 12:53, David Kastrup <address@hidden> wrote:
>
>> "Phil Holmes" <address@hidden> writes:
>> 
>>>> I have a hard time considering the output of
>>> 
>>>> \version "2.16.0"
>>>> 
>>>> \relative c' {
>>>> \set tupletSpannerDuration = #(ly:make-moment 1 2)
>>>> \times 2/3 { c8 d e f g a g f e d c d }
>>>> \set tupletSpannerDuration = #(ly:make-moment 1 4)
>>>> \times 2/3 { c4 d e f g a g f e d c d }
>>>> }
>>>> 
>>>> 
>>>> useful:
>>> 
>>> I think that looks OK?
>> 
>> No.  In the first case, the beaming should be 2+2+2 rather than 3+3: the
>> whole point is that there is supposed to be a subdivision into three,
>> and 3+3 defeats that.
>
> Hindemith, "Elementary training", p. 116, gives the rule that triplets
> are tripartite and sextuplet bipartite.

But the tuplet brace extends the tripartition to six notes, yielding
three groups of two, contrary to the beaming.

-- 
David Kastrup