Hi, Rainer:
I've following code:
<c d g>1\arpeggio ~ | << <c d g>1\fermata \\ {r2 r4 b'32 (c d e f g
a b)} >>
According to the documentation the two "<c d g>" should be tied.
Unfortunately this is not the case. Could you help me please?
Well, you've run into a subtlety of Lilypond that could, perhaps, be
better documented... ;-)
Consider the following code snippet:
%%% BEGIN SNIPPET %%%
\version "2.9.17"
\paper
{
indent = 0\in
line-width = 3\in
}
theMusic = \relative c'
{
<c d g>1 ~ | << <c d g>1\fermata \\ { s2 c4 c } >> \break
<c d g>1 ~ | << { <c d g>1\fermata } \new Voice { s2 c4 c } >>
}
\score
{
\theMusic
}
%%% END SNIPPET %%%
Notice that the tie does not work "as expected" in the first example,
but does in the second.
This is because, in the first example, the << \\ >> construct
explicitly instantiates TWO voices, BOTH of which are in addition to
the one which contains the <c d g> that starts the tie -- as a
result, the tie doesn't know where to end, because its Voice doesn't
continue on into the <<>> block.
In the second example, the \\ is replaced by an explicit (manual)
instantiation using \new Voice -- this ensures that anything before
the \new Voice command is considered part of the Voice that existed
before the <<>> block began, and so the tie knows where to terminate.
Does that make sense?
Or, at the very least, does it explain why you're seeing what you're
seeing? =)
Best regards,
Kieren.