Re: Bug in $(call ...) ?

[Alexey Neyman]

On Monday 20 December 2004 18:14, you wrote:
> Double dollar sign causes a single dollar sign literal to be present 
> in the string.  I don't think that is what you want here.

Yes, but that dollar sign is accompanied by a left parenthesis, digit 
and a right parenthesis. I'd assume this character sequence to be 
replaced with positional argument when this string is passed as $(0) 
to the $(call). I mixed in comments to illustrate the way I assumed 
the evaluation should happen. Please point me to the line where I 
made a mistake.

X = echo
A = $($(1)) $$(1) $$(2)

# $(0) = "$($(1)) $$(1) $$(2)"
# $(1) = X
# -> B = "echo $(1) $(2)"
B := $(call A,X)

# should be the same string as $(B), right ?
C = echo $(1) $(2)

all:
# $(0) = "echo $(1) $(2)"
# $(1) = "hi"
# $(2) = "lo"
# -> $(call B,hi,lo) should be "echo hi lo",
# but instead is "echo $(1) $(2)"
        @echo '[$(call B,hi,lo)]'
# $(0) = "echo $(1) $(2)"
# $(1) = "hi"
# $(2) = "lo"
# -> $(call B,hi,lo) is "echo hi lo", as it should be.
        @echo '[$(call C,hi,lo)]'

> >         > On Mon, Dec 20, 2004 at 05:56:33PM +0300, Alexey Neyman 
wrote: 
> > Well, I'll use it, thanks. However, it seems that it's actually a 
> > workaround. Perhaps this Makefile will illustrate better what I 
mean:
> > 
> > <<<<
> > X = echo
> > A = $($(1)) $$(1) $$(2)
> > B := $(call A,X)
> > C = echo $(1) $(2)
> > 
> > $(warning "$(value B)")
> > $(warning "$(value C)")
> > 
> > all:
> >         @echo '[$(call B,hi,lo)]'
> >         @echo '[$(call C,hi,lo)]'
> > >>>>
> > 
> > Note that the $(warning)s show that the values of B and C are the 
> > same. Yet, the results of echo differ:
> > 
> > Makefile:6: "echo $(1) $(2)"
> > Makefile:7: "echo $(1) $(2)"
> > [echo $(1) $(2)]
> > [echo hi lo]
> > 
> > 
> > On Monday 20 December 2004 16:33, you wrote:
> > > Perhaps the following modifications get you what you want.  I 
think
> > > perhaps you are just missing the passthrough for the numbered 
> > parameters
> > > for B.
> > > 
> > > X = echo
> > > A = $($(1)) $(2) $(3)
> > > B = $(call A,X,$(1),$(2))
> > > 
> > > all:    
> > >         @echo '[$(B)]'
> > >         @echo '[$(call B,hi,lo)]'
> > >         $(call B,hi,lo)
> > > 
> > >   Ken
> > > 
> > > On Mon, Dec 20, 2004 at 01:40:02PM +0300, Alexey Neyman wrote:
> > > > Hi,
> > > > 
> > > > address@hidden:~/tmp> cat Makefile
> > > > X = echo
> > > > A = $($(1)) $$(1) $$(2)
> > > > B = $(call A,X)
> > > > 
> > > > all:
> > > >         @echo '[$(B)]'
> > > >         @echo '[$(call B,hi,lo)]'
> > > > address@hidden:~/tmp> make all
> > > > [echo $(1) $(2)]
> > > > [echo $(1) $(2)]
> > > > 
> > > > I thought the "$(call B,hi,lo)" should have evaluated to "echo 
hi 
> > lo", 
> > > > shouldn't it?
> > > > 
> > > > Regards,
> > > > Alexey.
> > > > 
> > > > -- 
> > > > Ah, an insult... a sometimes necessary and constructive 
release of 
> > > > tension.
> > > >                         -- Pkunks, SC2
> > > > 
> > > > 
> > > > _______________________________________________
> > > > Help-make mailing list
> > > > address@hidden
> > > > http://lists.gnu.org/mailman/listinfo/help-make
> > > 
> > 
> > -- 
> > All are welcome to our nest.
> > We are Pkunk, we cannot help but love all.
> >                         -- Pkunks, SC2
> 

-- 
Try to understand 'em, but can you?
Nope, they're mysteries!
                        -- Pkunks, SC2