Re: Bug in $(call ...) ?

[Ken Smith]

Perhaps the following modifications get you what you want.  I think
perhaps you are just missing the passthrough for the numbered parameters
for B.

X = echo
A = $($(1)) $(2) $(3)
B = $(call A,X,$(1),$(2))

all:    
        @echo '[$(B)]'
        @echo '[$(call B,hi,lo)]'
        $(call B,hi,lo)

  Ken

On Mon, Dec 20, 2004 at 01:40:02PM +0300, Alexey Neyman wrote:
> Hi,
> 
> address@hidden:~/tmp> cat Makefile
> X = echo
> A = $($(1)) $$(1) $$(2)
> B = $(call A,X)
> 
> all:
>         @echo '[$(B)]'
>         @echo '[$(call B,hi,lo)]'
> address@hidden:~/tmp> make all
> [echo $(1) $(2)]
> [echo $(1) $(2)]
> 
> I thought the "$(call B,hi,lo)" should have evaluated to "echo hi lo", 
> shouldn't it?
> 
> Regards,
> Alexey.
> 
> -- 
> Ah, an insult... a sometimes necessary and constructive release of 
> tension.
>                         -- Pkunks, SC2
> 
> 
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