Re: Why is FUNC in cl-callf not allowed to be an expression?

[Michael Heerdegen]

Noam Postavsky <address@hidden> writes:

> > > >   (cl-callf (with (if flag #'1+ #'1-)) my-number)
>
> > OTOH, it probably wouldn't be good idea to complicate cl-callf if we
> > also want to add other stuff.
>
> Yeah, why not use something like
>
> (funcallf (if flag #'1+ #'1-) my-number)

FWIW, at least you can already write this as

  (cl-callf2 funcall (if flag #'1+ #'1-) my-number)

Michael.