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Re: Why is FUNC in cl-callf not allowed to be an expression?


From: Noam Postavsky
Subject: Re: Why is FUNC in cl-callf not allowed to be an expression?
Date: Tue, 21 May 2019 06:16:09 -0400

On Mon, 20 May 2019 at 22:47, Michael Heerdegen
<address@hidden> wrote:

> > >   (cl-callf (with (if flag #'1+ #'1-)) my-number)

> OTOH, it probably wouldn't be good idea to complicate cl-callf if we
> also want to add other stuff.

Yeah, why not use something like

(funcallf (if flag #'1+ #'1-) my-number)



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