Re: Idea: jobs(1) -i to print only :%ID:s

[Steffen Nurpmeso]

Greg Wooledge wrote in
 <ZU0xybd3KCs6MqdX@wooledge.org>:
 |On Thu, Nov 09, 2023 at 08:09:23PM +0100, Steffen Nurpmeso wrote:
 |>   j() {
 |>     local j= a=${AWK:-awk}
 |>     [ $# -gt 0 ] && j='&& $2 !~ /(^| )('$(echo "$@" | tr ' ' '|')')( \
 |>     |$)/'
 |>     j=$(jobs -l | $a -F '[][]' '/^[[]/'"$j"'{print "%" $2}{next}')
 |>     echo $j
 |>}
 |
 |Classic code injection vulnerability.

Well this is for me on my command line.  ash(1) and busybox ash(1)
do not even support jobs -l in a function (yet).  (Where??)

 |What are we even parsing?  Start with the input:
 |
 |unicorn:~$ sleep 5 &
 |[1] 849028
 |unicorn:~$ jobs -l
 |[1]+ 849028 Running                 sleep 5 &
 |
 |OK, so you wanted to strip the "1" from "[1]" and turn that into "%1",
 |yes?  That shouldn't be terribly hard in pure bash.
 |
 |    re='^\[([0-9]+)\]'
 |    jobspecs=()
 |    while IFS= read -r line; do
 |        if [[ $line =~ $re ]]; then

This is indeed a nice approach.  I have now spend over an hour
stupid me, and have no more time to extend this to filter out the
unwanted jobs, but i copy your thing over to my ~/.profile for
a future full implementation!  (Likely selectively after testing
which shells actually do support this syntax, ie ksh and such.)

 |            jobspecs+=( "%${BASH_REMATCH[1]}" )
 |        fi
 |    done < <(jobs -l)
 |
 |Wrap that in a function with local declarations, etc.

Thanks!
Ciao,

--steffen
|
|Der Kragenbaer,                The moon bear,
|der holt sich munter           he cheerfully and one by one
|einen nach dem anderen runter  wa.ks himself off
|(By Robert Gernhardt)