Re: Idea: jobs(1) -i to print only :%ID:s

[Greg Wooledge]

On Thu, Nov 09, 2023 at 08:09:23PM +0100, Steffen Nurpmeso wrote:
>   j() {
>     local j= a=${AWK:-awk}
>     [ $# -gt 0 ] && j='&& $2 !~ /(^| )('$(echo "$@" | tr ' ' '|')')( |$)/'
>     j=$(jobs -l | $a -F '[][]' '/^[[]/'"$j"'{print "%" $2}{next}')
>     echo $j
>   }

Classic code injection vulnerability.

What are we even parsing?  Start with the input:

unicorn:~$ sleep 5 &
[1] 849028
unicorn:~$ jobs -l
[1]+ 849028 Running                 sleep 5 &

OK, so you wanted to strip the "1" from "[1]" and turn that into "%1",
yes?  That shouldn't be terribly hard in pure bash.

    re='^\[([0-9]+)\]'
    jobspecs=()
    while IFS= read -r line; do
        if [[ $line =~ $re ]]; then
            jobspecs+=( "%${BASH_REMATCH[1]}" )
        fi
    done < <(jobs -l)

Wrap that in a function with local declarations, etc.