|Subject:||Re: Password and login question|
|Date:||Fri, 9 Jul 2021 13:31:29 -0400|
On Fri, 9 Jul 2021 at 17:23, Evan Meyer via <email@example.com> wrote:
> After running the command
> build$ runqemu qemux86 core-image-apd-devel nographic \
> qemuparams="-net socket,mcast=188.8.131.52:30490"
> It takes me to a page that looks like this ...
> [ 5.387318] Freeing unused kernel image memory: 900K
> [ 5.387907] Write protecting kernel text and read-only data: 12604k
> [ 5.388230] Run /sbin/init as init process
> [ 5.462766]~DLT~ 1~INFO ~FIFO /tmp/dlt cannot be opened. Retrying later...
> 2021/07/09 16:15:21.488045 54753 000 ECU1 EXEC INTM log info V 1 [Enabled console output.]
> 2021/07/09 16:15:21.496657 54837 001 ECU1 EXEC INTM log info V 2 [Init DLT back-end done, all known contexts set to default log l]
> [ 7.087114] sched: RT throttling activated
> [ 7.088860] hrtimer: interrupt took 1995123 ns
> APD R20-11 192.168.7.2 /dev/ttyS0
> 192.168.7.2 login:
> Where did I set the login for this, and where can I find out where to get this information. I have tried every password that I know of ever using but I cannot seem to get it, and any help would be greatly appreciated.
This is the guest OS you are running inside QEMU prompting for a
password. The expected user/password will depend entirely on what that
guest OS image is. You should look at the documentation for whatever
source you got the guest OS from.
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