Re: 'for' loop on elements of cell array (octave-3.4.2) - is it the way it is supposed to be ?

[Ben Abbott]

On Feb 2, 2012, at 6:39 AM, Sergei Steshenko wrote:

> Hello,
> 
> I have tried the following piece of code:
> 
> "
> octave:1> foolist = {1, 2, 5}
> foolist =
> {
>   [1,1] =  1
>   [1,2] =  2
>   [1,3] =  5
> }
> octave:2> for foo = foolist foo endfor
> foo =
> {
>   [1,1] =  1
> }
> foo =
> {
>   [1,1] =  2
> }
> foo =
> {
>   [1,1] =  5
> }

<snip>

> In other words, the output from the 'for' loop doesn't look like I expect, 
> and if my expectations (I expected '1, 2, 5' sequence) are wrong, which part 
> of GNU Octave documentations explains how the output should look ?

I'm confused. The output is 1, 2, 5.

The for loop below will run 3 times (once for each column)

for a = [1 2 3; 4 5 6; 7 8 9]
  disp (a)
  disp ('---')
end
   1
   4
   7
---
   2
   5
   8
---
   3
   6
   9
---

This one will only perform one loop

for a = [1 2 3; 4 5 6; 7 8 9](:)
  disp (a)
  disp ('---')
end
   1
   4
   7
   2
   5
   8
   3
   6
   9
---

And this one will perform 9 loops

for a = [1 2 3; 4 5 6; 7 8 9](:)'
  disp (a)
  disp ('---')
end
 1
---
 4
---
 7
---
 2
---
 5
---
 8
---
 3
---
 6
---
 9
---

Does that clarify the behavior ? 

Ben