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## Re: [Bug-gnubg] (OT) Position ID documentation

 From: bgnj Subject: Re: [Bug-gnubg] (OT) Position ID documentation Date: Sat, 5 Jun 2010 22:57:34 -0700 (PDT)

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Massimiliano Maini-3 wrote:
>
> I did the computation this way:
>
> # Non-contact positions.
> NC_pos = 0
> for lop in range(1,23+1):
>       # Black has 1 checker on point lop, 15-1 checkers on points
>       # 0..lop (0 meaning off).
>       # White can be on points lop+1..25 (25 meaning off), but at
>       # least one is on points lop+1..24. Nobody is on the bar.
>       NC_pos += Dnm(lop+1,15-1)*(Cnm(24-(lop+1)+1,1)*Dnm(25-(lop+1)+1,15-1))
>
> I get this:
>
> Non-contact positions: 9350831674578000 (9E+15).
>

Massimiliano, I think your formula is incorrect.  For white, you have:

White = (Cnm(24-(lop+1)+1,1)*Dnm(25-(lop+1)+1,15-1))

With the explanation:

# White can be on points lop+1..25 (25 meaning off), but at
# least one is on points lop+1..24. Nobody is on the bar.

I think from your explanation, it should be:

White = Dnm(25-lop+1, 15) - 1

where the -1 accounts for the one case that all checkers are off.  For
example, if lop = 22, and therefore white has 3 spaces to distribute 15

White = Cnm(2, 1) * Dnm(3, 14) = 2 * 120 = 240

But that number exceeds the total number of ways to distribute 15 checkers
on 3 spaces, which is:

Dnm(3, 15) = 136

Your formula gives the number of ways to distribute 15 checkers with 1
checker being distinguishable from all other checkers (and this special
checker is not in the tray).  This number is larger than the case where all
checkers are indistinguishable from each other.  I hope that made sense.

- BGNJ
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