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list (comma) operator
From: |
john43 |
Subject: |
list (comma) operator |
Date: |
Wed, 18 Jun 2003 18:32:48 -0400 |
Hi,
The manual says that the list operator evaluates to the value
of its right-most operand. However, I'm seeing the opposite:
$ touch a b
$ find '(' -name a , -name b ')' -print
./a
>From the manual: (GNU find version 4.1)
expr1 , expr2
List; both expr1 and expr2 are always
evaluated. The value of expr1 is
discarded; the value of the list is the
value of expr2.
-John
- list (comma) operator,
john43 <=