Re: list (comma) operator

[James Youngman]

On Wed, Jun 18, 2003 at 06:32:48PM -0400, address@hidden wrote:
> Hi,
> 
> The manual says that the list operator evaluates to the value
> of its right-most operand. However, I'm seeing the opposite:
> 
> $ touch a b
> $ find  '(' -name a , -name b ')' -print
> ./a

Very odd - I see a different result with findutils 4.1.7 and the
current CVS code (4.2.0-CVS).  I haven't checked 4.1.20, but I'm sure
it would give the same result here as 4.2.0-CVS.  

address@hidden:~$ find --version
GNU find version 4.1.7
address@hidden:~$ rm a b ; touch a b ; find  '(' -name a , -name b ')' -print
./b


address@hidden:~$ ~/source/GNU/findutils/trunk/compile.i386/find/find '(' -name 
a , -name b ')' -print
./b
address@hidden:~$ ~/source/GNU/findutils/trunk/compile.i386/find/find --version 
 GNU find version 4.2.0-CVS


> 
> 
> >From the manual: (GNU find version 4.1)
> 
>    expr1 , expr2
> 
>        List;  both  expr1 and expr2 are always
>        evaluated.  The value of expr1 is
>        discarded; the value of the list is the
>        value of expr2.
>