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Re: [Qemu-ppc] [Qemu-devel] [PATCH v2 1/4] target-ppc: Implement bcdcfsq


From: Richard Henderson
Subject: Re: [Qemu-ppc] [Qemu-devel] [PATCH v2 1/4] target-ppc: Implement bcdcfsq. instruction
Date: Thu, 24 Nov 2016 01:43:18 +0100
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:45.0) Gecko/20100101 Thunderbird/45.4.0

On 11/23/2016 05:21 PM, Jose Ricardo Ziviani wrote:
bcdcfsq.: Decimal convert from signed quadword. It is not possible
to convert values less than 10^31-1 or greater than -10^31-1 to be
represented in packed decimal format.

Signed-off-by: Jose Ricardo Ziviani <address@hidden>
---
 target-ppc/helper.h                 |  1 +
 target-ppc/int_helper.c             | 45 +++++++++++++++++++++++++++++++++++++
 target-ppc/translate/vmx-impl.inc.c |  7 ++++++
 3 files changed, 53 insertions(+)

diff --git a/target-ppc/helper.h b/target-ppc/helper.h
index da00f0a..87f533c 100644
--- a/target-ppc/helper.h
+++ b/target-ppc/helper.h
@@ -382,6 +382,7 @@ DEF_HELPER_3(bcdcfn, i32, avr, avr, i32)
 DEF_HELPER_3(bcdctn, i32, avr, avr, i32)
 DEF_HELPER_3(bcdcfz, i32, avr, avr, i32)
 DEF_HELPER_3(bcdctz, i32, avr, avr, i32)
+DEF_HELPER_3(bcdcfsq, i32, avr, avr, i32)

 DEF_HELPER_2(xsadddp, void, env, i32)
 DEF_HELPER_2(xssubdp, void, env, i32)
diff --git a/target-ppc/int_helper.c b/target-ppc/int_helper.c
index 8886a72..751909c 100644
--- a/target-ppc/int_helper.c
+++ b/target-ppc/int_helper.c
@@ -2874,6 +2874,51 @@ uint32_t helper_bcdctz(ppc_avr_t *r, ppc_avr_t *b, 
uint32_t ps)
     return cr;
 }

+uint32_t helper_bcdcfsq(ppc_avr_t *r, ppc_avr_t *b, uint32_t ps)
+{
+    int cr;
+    int i;
+    int ox_flag = 0;
+    uint64_t lo_value;
+    uint64_t hi_value;
+    uint64_t max = 0x38d7ea4c68000;

This is at heart a decimal number, and should be written as such.
Also, you need ULL for a 32-bit host compile.

+    if (divu128(&lo_value, &hi_value, max)) {
+        ox_flag = 1;
+    } else if (lo_value >= max && hi_value == 0) {
+        ox_flag = 1;
+    }

Dispense with ox_flag and set cr = CRF_SO now.

+    for (i = 1; hi_value; hi_value /= 10, i++) {
+        bcd_put_digit(&ret, hi_value % 10, i);
+    }
+
+    for (; lo_value; lo_value /= 10, i++) {
+        bcd_put_digit(&ret, lo_value % 10, i);
+    }

How can this possibly work? You know there are 15 digits between high and low, but you continue with i++?

If hi_value == 1 && lo_value == 1, this should not produce 11, but 10000000000000001.


r~



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