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From: | Anthony Liguori |
Subject: | Re: [Qemu-devel] Is this an invalid combination? |
Date: | Tue, 15 Feb 2011 14:21:41 -0600 |
User-agent: | Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.1.15) Gecko/20101027 Lightning/1.0b1 Thunderbird/3.0.10 |
On 02/15/2011 02:07 PM, Bruce Rogers wrote:
Hi, We just noticed an issue flagged by a libvirt based test. This same command line didn't used to fail, and I wanted to be sure that this is behaving as intended. When the following command line is used on the current qemu version: x86_64-softmmu/qemu-system-x86_64 -kernel /boot/vmlinuz -drive file=~/disk0.raw,if=none,id=foo,boot=on -device virtio-blk-pci,drive=foo We get the following error reported: Two devices with same boot index 0 Previous versions of qemu did not flag this as an error condition.
Upstream QEMU does not have a boolean boot flag although I guess we ignore it in -drive which sucks :-/
In upstream QEMU, the BIOS can boot just fine from a virtio device. What you're seeing is that we've apparently overloaded the boot flag in upstream qemu to mean boot index.
Gleb, what's the right invocation here? Regards, ANthony Liguori
I can see that we are indicating two different boot sources here, so I would guess the command line is invalid, but wanted to be sure. Bruce
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