Re: [Qemu-devel] Is this an invalid combination?

[Gleb Natapov]

On Tue, Feb 15, 2011 at 02:21:41PM -0600, Anthony Liguori wrote:
> On 02/15/2011 02:07 PM, Bruce Rogers wrote:
> >Hi,
> >
> >We just noticed an issue flagged by a libvirt based test.  This same command 
> >line didn't used to fail, and I wanted to be sure that this is behaving as 
> >intended.
> >
> >When the following command line is used on the current qemu version:
> >
> >x86_64-softmmu/qemu-system-x86_64 -kernel /boot/vmlinuz -drive 
> >file=~/disk0.raw,if=none,id=foo,boot=on -device virtio-blk-pci,drive=foo
> >
> >We get the following error reported:
> >Two devices with same boot index 0
> >
> >Previous versions of qemu did not flag this as an error condition.
> 
> Upstream QEMU does not have a boolean boot flag although I guess we
> ignore it in -drive which sucks :-/
> 
> In upstream QEMU, the BIOS can boot just fine from a virtio device.
> What you're seeing is that we've apparently overloaded the boot flag
> in upstream qemu to mean boot index.
> 
> Gleb, what's the right invocation here?
> 
Just drop boot=on. Qemu-kvm registers extboot and some other bootrom
(which one?) with the same boot index. This should be fixed, but
dropping boot=on is the right solution in any case. Actually I want to
remove extboot from qemu-kvm at all. It will not make it upstream
anyway.


> Regards,
> 
> ANthony Liguori
> 
> >I can see that we are indicating two different boot sources here, so I would 
> >guess the command line is invalid, but wanted to be sure.
> >
> >Bruce
> >
> >

--
                        Gleb.