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RE: Select elements according to the index
From: |
Chen, Minyu |
Subject: |
RE: Select elements according to the index |
Date: |
Sun, 13 Feb 2005 18:25:52 -0000 |
Thank you both. It was not working in 2.1.40 which came directly with my
Red Hat 9. However, as I just upgraded the package to 2.1.64, it works
perfectly.
Thanks,
Minyu Chen
-----Original Message-----
From: Henry F. Mollet [mailto:address@hidden
Sent: 13 February 2005 17:30
To: Todd Neal; Chen, Minyu
Cc: Octave_post
Subject: Re: Select elements according to the index
octave:24> a=[1 2 3; 4 5 6]
a =
1 2 3
4 5 6
octave:25> b=[.1 .2 .3 .4 .5 .6 .7 .8]
b =
0.10000 0.20000 0.30000 0.40000 0.50000 0.60000 0.70000 0.80000
octave:26> c=b(a)
c =
0.10000 0.20000 0.30000
0.40000 0.50000 0.60000
Works on
GNU Octave, version 2.1.46 (powerpc-apple-darwin6.6).
Henry
>
> What version of Octave are you using ? This is from 2.1.64 Debian
Testing.
>
> octave:1> a=[1 2 3; 4 5 6];
> octave:2> b=[.1 .2 .3 .4 .5 .6 .7 .8];
> octave:3> c=b(a)
> c =
>
> 0.10000 0.20000 0.30000
> 0.40000 0.50000 0.60000
>
>
> Todd
>
on 2/13/05 8:04 AM, Todd Neal at address@hidden wrote:
> On Sun, 13 Feb 2005 13:32:25 -0000, Chen, Minyu <address@hidden>
wrote:
> ...
>> Suppose I have an index matrix of 2 by 3, e.g. a=[1 2 3; 4 5 6]
>>
>> And have a vector of 1 by 8, e.g. b=[.1 .2 .3 .4 .5 .6 .7 .8]
>>
>> And I want to create a matrix c of 2 by 3 (the same dimension of a),
>> with c(i,j)=b(a(i,j)), that's being said:
>>
>> c=[.1 .2 .3; .4 .5 .6]
>>
>> In matlab, as memory serves correctly, I can do it by typing:
>>
>> c=b(a)
>>
>> but this command in Octave will generate only a vector of 1 by 6:
>>
>> c=[.1 .4 .2 .5 .3 .6]
>>
>> How can I get the matrix I want?
>>
>> Many Thanks,
>> Minyu Chen
>
>
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