Re: Select elements according to the index

[Todd Neal]

On Sun, 13 Feb 2005 13:32:25 -0000, Chen, Minyu <address@hidden> wrote:
...
> Suppose I have an index matrix of 2 by 3, e.g. a=[1 2 3; 4 5 6]
> 
> And have a vector of 1 by 8, e.g. b=[.1 .2 .3 .4 .5 .6 .7 .8]
> 
> And I want to create a matrix c of 2 by 3 (the same dimension of a),
> with c(i,j)=b(a(i,j)), that's being said:
> 
> c=[.1 .2 .3; .4 .5 .6]
> 
> In matlab, as memory serves correctly, I can do it by typing:
> 
> c=b(a)
> 
> but this command in Octave will generate only a vector of 1 by 6:
> 
> c=[.1 .4 .2 .5 .3 .6]
> 
> How can I get the matrix I want?
> 
> Many Thanks,
> Minyu Chen

What version of Octave are you using ?  This is from 2.1.64 Debian Testing.

octave:1> a=[1 2 3; 4 5 6];
octave:2> b=[.1 .2 .3 .4 .5 .6 .7 .8];
octave:3> c=b(a)
c =

  0.10000  0.20000  0.30000
  0.40000  0.50000  0.60000


Todd



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