Re: lua 'grub.run' does not return message text

[edgar . soldin]

thanks .. I am gonna double check this. Are their other undocumented 
variables like grub_errmsg. Where should I look for documentation? I'd 
also look at the source if necessary.

About what I am doing. I found the listiso scripts
http://ubuntuforums.org/showthread.php?t=1288604
while trying to get them up and running they silently died because of 
missing modules. Essentially I wanted to parse lsmod. Because that's 
currently not possible I simply check if insmod fails or not.

Do you have an idea on how to parse grub.run output in the current state 
of the lua module?

Thanks again .. ede


On 17.01.2010 00:48, Jordan Uggla wrote:
> On Thu, Jan 14, 2010 at 1:12 PM,<address@hidden>  wrote:
> > When I run
> >
> > err,msg = grub.run("ls")
> >
> > only the variable err is filled with the exit code.
> > msg is still nil .. I saw documentation that grub.run is supposed to return
> > the output in the second variable.
>
> In the latest bzr ( pushed a few minutes ago ) the interface matches
> what is documented in http://grub.enbug.org/LUASupport . Be careful
> though, it's only the error message that is returned, not the output
> of "ls". And an error message is only returned if there is an error.
> For example:
>
> errno, err_msg = grub.run( "ls /boot") --Outputs "grub/"
> print( errno, err_msg ) -- Outputs "0        nil"
>
> errno, err_msg = grub.run( "ls /boot/nonexistent" ) -- Outputs nothing
> print( errno, err_msg ) -- Outputs "5        file not found"
>
> If you want to actually list and store devices / files from lua you
> should use grub.enum_device() and grub.enum_file() .