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Re: [Qemu-trivial] [PATCH] qapi: cleanup redundant variable
From: |
Michael Tokarev |
Subject: |
Re: [Qemu-trivial] [PATCH] qapi: cleanup redundant variable |
Date: |
Sat, 01 Feb 2014 13:49:11 +0400 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:17.0) Gecko/20131103 Icedove/17.0.10 |
23.01.2014 12:54, Amos Kong wrote:
> No need to re-append an expr list, it's ok to return schema.exprs
>
> Signed-off-by: Amos Kong <address@hidden>
> ---
> scripts/qapi.py | 5 +----
> 1 file changed, 1 insertion(+), 4 deletions(-)
>
> diff --git a/scripts/qapi.py b/scripts/qapi.py
> index 7b92689..718f1ad 100644
> --- a/scripts/qapi.py
> +++ b/scripts/qapi.py
> @@ -175,8 +175,6 @@ def parse_schema(fp):
> print >>sys.stderr, e
> exit(1)
>
> - exprs = []
> -
> for expr in schema.exprs:
> if expr.has_key('enum'):
> add_enum(expr['enum'])
> @@ -185,9 +183,8 @@ def parse_schema(fp):
> add_enum('%sKind' % expr['union'])
> elif expr.has_key('type'):
> add_struct(expr)
> - exprs.append(expr)
>
> - return exprs
> + return schema.exprs
I don't really know python. Does it mean that previously,
this function returned a copy of schema.exprs, but now it
returns schema.exprs itself, so a caller can modify it?
Thanks,
/mjt
- Re: [Qemu-trivial] [PATCH] qapi: cleanup redundant variable,
Michael Tokarev <=