[Qemu-discuss] signal SIGILL, Illegal instruction for "mtc0 zero, c0_cause"

[G 3]

On Apr 14, 2017, at 12:00 PM, address@hidden wrote:

> Message: 1
> Date: Fri, 14 Apr 2017 07:31:49 +0000
> From: "Zhangwen (Esan)" <address@hidden>
> To: "address@hidden" <address@hidden>
> Subject: [Qemu-discuss] signal SIGILL, Illegal instruction for "mtc0
>         zero, c0_cause"
> Message-ID:
> 	<address@hidden 
> MBS.china.huawei.com>
>         
> Content-Type: text/plain; charset="us-ascii"
>
> Hi,
>   When I run a binary with qemu-2.7.1, I found it report a error:
> Program received signal SIGILL, Illegal instruction.
>   Then I gdb it, the scene is as follows:
> (gdb) si
>
> Program received signal SIGILL, Illegal instruction.
> _start () at ../newlib-2.2.0/libgloss/mips/crt0.S:92
> 92              nop
> (gdb) disass
> Dump of assembler code for function _start:
> => 0x00000040 <+0>:     mtc0    zero,c0_cause
>    0x00000044 <+4>:     nop
>
> The binary is compiled with newlib-2.2.0, but it works with  
> glibc-2.20.
> "mtc0" instruction can not be recognized by qemu-2.7.1 or any others?
> So I have no idea what happened and could anybody explain the reason?

Which machine are you trying to emulate?