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Re: [bash 4] 'test -v 1' is never true
From: |
G. Branden Robinson |
Subject: |
Re: [bash 4] 'test -v 1' is never true |
Date: |
Fri, 25 Nov 2022 15:40:42 -0600 |
Hi Alex,
At 2022-11-25T22:02:46+0100, Alejandro Colomar wrote:
> I wrote a script, and am trying it on many systems. On RHEL8, which
> has bash 4, it didn't work. I could reduce the problem to the
> following command, which never returns true:
>
> test -v 1;
>
> In Debian Sid, where I develop, and where I have bash 5, that works
> fine, and is true if the function or script in which it is has any
> arguments. On zsh(1) it also works fine.
>
> Is this a known bug in bash?
> The exact version where I can reproduce it is 4.4.20(1)-release
> (x86_64-redhat-linux-gnu).
I don't think it is a bug. It is unspecified behavior according to
POSIX.
"-v" is not an operator according to POSIX, and I don't recall seeing it
in any shell. It is therefore interpreted as a string argument.
The algorithm for determining the precedence of the operators and the
return value that shall be generated is based on the number of
arguments presented to test. (However, when using the "[...]" form,
the right-bracket final argument shall not be counted in this
algorithm.)
In the following list, $1, $2, $3, and $4 represent the arguments
presented to test:
0 arguments:
Exit false (1).
1 argument:
Exit true (0) if $1 is not null; otherwise, exit false.
2 arguments:
If $1 is '!', exit true if $2 is null, false if $2 is not
null.
If $1 is a unary primary, exit true if the unary test is true,
false if the unary test is false.
Otherwise, produce unspecified results.
https://pubs.opengroup.org/onlinepubs/009695299/utilities/test.html
Regards,
Branden
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