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Re: local/typeset/declare -p - outputs invalid declare -- -


From: Alex fxmbsw7 Ratchev
Subject: Re: local/typeset/declare -p - outputs invalid declare -- -
Date: Mon, 31 Oct 2022 18:12:14 +0100

hi , sorry.. whats the purpose of local -
informational question

On Mon, Oct 31, 2022, 17:45 Emanuele Torre <torreemanuele6@gmail.com> wrote:

> Since bash 5.2,  local/typeset/declare -p  without argument no longer
> outputs "declare -- -" when  local -  is used.
>
> But  local/typeset/declare -p -  still outputs "declare -- -" instead of
> "local -".
>
>     bash-5.1$ a () { local -; local -p; declare -p -; typeset -p -;
> local -p - ;}
>     bash-5.1$ a
>     declare -- -
>     declare -- -
>     declare -- -
>     declare -- -
>
>     bash-5.2$ a () { local -; local -p; declare -p -; typeset -p -;
> local -p - ;}
>     bash-5.2$ a
>     local -
>     declare -- -
>     declare -- -
>     declare -- -
>
>


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