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Re: $(()): "?:": false "assignment to non-variable"
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From: |
Andreas Schwab |
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Subject: |
Re: $(()): "?:": false "assignment to non-variable" |
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Date: |
Mon, 11 Jul 2022 14:46:04 +0200 |
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User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/28.1.90 (gnu/linux) |
On Jul 09 2022, Steffen Nurpmeso wrote:
> $ bash -c 'I=3; echo "$((1?(I*=I):I+=I))";echo $I'
The third operand of ?: cannot contain an assignment expression, thus,
like in C, this is parsed as `(1?(I*=I):I)+=I'.
--
Andreas Schwab, SUSE Labs, schwab@suse.de
GPG Key fingerprint = 0196 BAD8 1CE9 1970 F4BE 1748 E4D4 88E3 0EEA B9D7
"And now for something completely different."