Re: remove list member during a forEach: traversal?

[Nelson Minar]

>The best workaround for now is to run your own loop (forEach doesn't
>do anything more than automate the loop) with your own index and have
>your myMsg remove the member using the index:
>  [currentIndex remove];

or if you just want to remove everything, call.
  [aCollection removeAll]
There's also
  [aCollection dropAll]
which also sends drop messages to all the objects. Beware of doing
this if there are duplicates in the collection.