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Re: [shell-script] Re: formatacao de um arquivo
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From: |
Herbert Alexander Faleiros |
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Subject: |
Re: [shell-script] Re: formatacao de um arquivo |
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Date: |
Thu, 6 Jul 2006 17:05:48 -0300 |
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User-agent: |
KMail/1.9.3 |
On Thursday 06 July 2006 16:33, Rafael Sanches wrote:
[cut]
> mudar o 4ยบ digito para 3 ou seja muda de 0 para 3.
[cut]
$ cat lista
14505230938800941627220060730004910000000024810000000150008512C
14505248938814460158920060730004920000000031280000000150008512C
14505234611810038825120060730004930000000032430000000150008512C
14505724472800072098020060730004940000000035680000000150008512C
14505731002800962258120060730004950000000025650000000600008512C
14505729837814945544020060730004960000000037640000000150008512C
14505732259800630209820060730004970000000031970000000150008512C
$ for i in `cat lista`;do echo ${i:0:3}3${i:4}; done
14535230938800941627220060730004910000000024810000000150008512C
14535248938814460158920060730004920000000031280000000150008512C
14535234611810038825120060730004930000000032430000000150008512C
14535724472800072098020060730004940000000035680000000150008512C
14535731002800962258120060730004950000000025650000000600008512C
14535729837814945544020060730004960000000037640000000150008512C
14535732259800630209820060730004970000000031970000000150008512C
$ sed -r 's/(^...).(.+)/\13\2/g' lista
14535230938800941627220060730004910000000024810000000150008512C
14535248938814460158920060730004920000000031280000000150008512C
14535234611810038825120060730004930000000032430000000150008512C
14535724472800072098020060730004940000000035680000000150008512C
14535731002800962258120060730004950000000025650000000600008512C
14535729837814945544020060730004960000000037640000000150008512C
14535732259800630209820060730004970000000031970000000150008512C