On 18.11.21 13:06, Philippe Mathieu-Daudé wrote:
From: Alexander Bulekov <alxndr@bu.edu>
Without the previous commit, when running 'make check-qtest-i386'
with QEMU configured with '--enable-sanitizers' we get:
AddressSanitizer:DEADLYSIGNAL
=================================================================
==287878==ERROR: AddressSanitizer: SEGV on unknown address
0x000000000344
==287878==The signal is caused by a WRITE memory access.
==287878==Hint: address points to the zero page.
#0 0x564b2e5bac27 in blk_inc_in_flight
block/block-backend.c:1346:5
#1 0x564b2e5bb228 in blk_pwritev_part block/block-backend.c:1317:5
#2 0x564b2e5bcd57 in blk_pwrite block/block-backend.c:1498:11
#3 0x564b2ca1cdd3 in fdctrl_write_data hw/block/fdc.c:2221:17
#4 0x564b2ca1b2f7 in fdctrl_write hw/block/fdc.c:829:9
#5 0x564b2dc49503 in portio_write softmmu/ioport.c:201:9
Add the reproducer for CVE-2021-20196.
Signed-off-by: Alexander Bulekov <alxndr@bu.edu>
Message-Id: <20210319050906.14875-2-alxndr@bu.edu>
[PMD: Rebased, use global test_image]
Reviewed-by: Darren Kenny <darren.kenny@oracle.com>
Signed-off-by: Philippe Mathieu-Daudé <philmd@redhat.com>
---
tests/qtest/fdc-test.c | 21 +++++++++++++++++++++
1 file changed, 21 insertions(+)
Not sure if I’m doing something wrong, but:
Using the global test_image brings a problem, namely that this test
fails unconditionally (for me at least...?), with the reason being that
the global QEMU instance (launched by qtest_start(), quit by
qtest_end()) still has that image open, so by launching a second
instance concurrently, I get this:
qemu-system-x86_64: Failed to get "write" lock
Is another process using the image [/tmp/qtest.xV4IxX]?