Re: [PATCH v3 2/7] gpiolib: Add support for gpiochipN-based table lookup

[Linus Walleij]

Hi Geert!

On Wed, Nov 27, 2019 at 9:43 AM Geert Uytterhoeven
<address@hidden> wrote:

> Currently GPIO controllers can only be referred to by label in GPIO
> lookup tables.
>
> Add support for looking them up by "gpiochipN" name, with "N" either the
> corresponding GPIO device's ID number, or the GPIO controller's first
> GPIO number.
>
> Signed-off-by: Geert Uytterhoeven <address@hidden>

What the commit message is missing is a rationale, why is this needed?

> If this is rejected, the GPIO Aggregator documentation must be updated.
>
> The second variant is currently used by the legacy sysfs interface only,
> so perhaps the chip->base check should be dropped?

Anything improving the sysfs is actively discouraged by me.
If it is just about staying compatible it is another thing.

> +static int gpiochip_match_id(struct gpio_chip *chip, void *data)
> +{
> +       int id = (uintptr_t)data;
> +
> +       return id == chip->base || id == chip->gpiodev->id;
> +}
>  static struct gpio_chip *find_chip_by_name(const char *name)
>  {
> -       return gpiochip_find((void *)name, gpiochip_match_name);
> +       struct gpio_chip *chip;
> +       int id;
> +
> +       chip = gpiochip_find((void *)name, gpiochip_match_name);
> +       if (chip)
> +               return chip;
> +
> +       if (!str_has_prefix(name, GPIOCHIP_NAME))
> +               return NULL;
> +
> +       if (kstrtoint(name + strlen(GPIOCHIP_NAME), 10, &id))
> +               return NULL;
> +
> +       return gpiochip_find((void *)(uintptr_t)id, gpiochip_match_id);

Isn't it easier to just  augment the existing match function to
check like this:

static int gpiochip_match_name(struct gpio_chip *chip, void *data)
{
        const char *name = data;

        if (!strcmp(chip->label, name))
               return 0;
        return !strcmp(dev_name(&chip->gpiodev->dev), name);
}

We should I guess also add some kerneldoc to say we first
match on the label and second on dev_name().

Yours,
Linus Walleij