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Re: [Qemu-devel] [PATCH 2/3] hw/net/spapr_llan: Fix receive buffer handl

From: Thomas Huth
Subject: Re: [Qemu-devel] [PATCH 2/3] hw/net/spapr_llan: Fix receive buffer handling for better performance
Date: Fri, 18 Mar 2016 08:56:56 +0100
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:38.0) Gecko/20100101 Thunderbird/38.6.0

On 17.03.2016 23:33, David Gibson wrote:
> On Thu, Mar 17, 2016 at 04:15:38PM +0100, Thomas Huth wrote:
>> On 17.03.2016 08:30, Thomas Huth wrote:
>>> On 17.03.2016 07:23, David Gibson wrote:
>>>> On Wed, Mar 16, 2016 at 01:16:50PM +0100, Thomas Huth wrote:
>>>>> This patch introduces an alternate way of handling the receive
>>>>> buffers of the spapr-vlan device, resulting in much better
>>>>> receive performance for the guest.
>> [...]
>>>>> +/**
>>>>> + * Enqueuing receive buffer by adding it to one of our receive buffer 
>>>>> pools
>>>>> + */
>>>>> +static target_long spapr_vlan_add_rxbuf_to_pool(VIOsPAPRVLANDevice *dev,
>>>>> +                                                target_ulong buf)
>>>>> +{
>>>>> +    int size = VLAN_BD_LEN(buf);
>>>>> +    int pool;
>>>>> +
>>>>> +    pool = spapr_vlan_get_rx_pool_id(dev, size);
>>>>> +
>>>>> +    /* No matching pool found? Try to create a new one */
>>>>> +    if (pool < 0) {
>>>>> +        for (pool = RX_MAX_POOLS - 1; pool >= 0 ; pool--) {
>>>> I don't think this loop actually accomplishes anything.  Either the
>>>> last slot is free, in which case you use it, then sort into place, or
>>>> it's not, in which case you've hit the maximum number of buffer pools.
>>> Oh, you're right. Well spotted! I'll rework my patch to do it without
>>> that loop.
>> Wait, no, there was a case where this loop is actually really required:
>> 1) All pools are in use and filled with at least one BD
>> 2) User in the guest suddenly decides to change the buffer size of
>>    one of the pools in the /sys fs of the guest.
>> 3) Guest driver tries to add buffers with a new size that do not
>>    match any size of one of the pools in the host
>> 4) After the pool on the host runs empty which contained the BDs with
>>    the size that is not in use anymore, we should recycle that pool
>>    for the buffers with the new size instead. Since that buffer pool
>>    might not be at the end of the list, we've got to scan all buffers
>>    here to make sure we find it.
>> So I think the for-loop should stay as it is.
> Ah, good point.  I think I was assuming that the pools got sorted when
> one was emptied as well, but they're not and I suspect it's not a good
> idea to do so.
> Hmm.. I wonder if there's a brief way of explaining the above to put
> in the comment.

Something like:

     * If the guest used all pools, but changed the size of one pool
     * inbetween, we might need to recycle that pool here (if it has
     * already been emptied). Thus we need to scan all buffer pools
     * here, not only the last one (which has the highest probability
     * of being empty)


Or is that too verbose already?


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