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[Qemu-devel] [Bug 424458] Re: PCI read data register offset
From: |
Alex Williamson |
Subject: |
[Qemu-devel] [Bug 424458] Re: PCI read data register offset |
Date: |
Wed, 02 Jun 2010 17:46:00 -0000 |
I think the problem is that you're trying to do a 4-byte read that goes
off the end of PCI_DATA. Try doing an inpw() to read the last word.
Simple test program shows it works properly for me.
** Changed in: qemu
Status: New => Invalid
--
PCI read data register offset
https://bugs.launchpad.net/bugs/424458
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Status in QEMU: Invalid
Bug description:
I may have found a bug with the PCI code.
If I execute the following code as a quest,
#define PCI_ADDR 0x0CF8
#define PCI_DATA 0x0CFC
// bus 0, dev 0, func 0, addr 0
outpd(PCI_ADDR, 0x80000000);
// read in the dword at addr 0 offset 0
// and
// read in the word at addr 0 offset 2
// and the word at addr 1 offset 0
printf("0x%08X 0x%08X", inpd(PCI_DATA), inpd(PCI_DATA+2));
Qemu (0.10.6 Windows build) returns
0x12378086 0xFFFFFFFF
It seems that if I read from any offset other than PCI_DATA, QEMU is returning
0xFFFFFFFF.
Shouldn't PCI_DATA+1, PCI_DATA+2, and PCI_DATA+3 all be registered to the PCI
emulation?
Again, this is the Windows build at
http://homepage3.nifty.com/takeda-toshiya/qemu/index.html
so it is unknown if it is the main CVS. I didn't check, though I can't image
this error lasting this long. I would image someone would have noticed it
already. So it might be assosiated with the Windows build only. Thanks.
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