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Re: [Qemu-devel] How does a system call work on QEMU?


From: grisu46
Subject: Re: [Qemu-devel] How does a system call work on QEMU?
Date: Thu, 14 May 2009 20:00:40 +0200
User-agent: Thunderbird 2.0.0.21 (Windows/20090302)

Avi Kivity ha scritto:
grisu46 wrote:
No. Look at target-i386/translate.c, case 0x105 for syscall emulation. Eventually it ends up calling helper_syscall().


Simplify?
I am a newbie.

Sorry, you're on your own. I can give you pointers but it's up to you to follow them. If you're serious about understanding qemu you should be prepared a lot of time reading the source code and processor documentation.

I would like to know how a virtualization program can perform a sensitive but not privileged operation. I learn about Xen and I like to understand (no deep details need) differences between Xen paravirtualization and QEMU emulator.

Thanks
Chiacchiera con i tuoi amici in tempo reale! http://it.yahoo.com/mail_it/foot/*http://it.messenger.yahoo.com




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