Re: Bug when dividing a scalar by a vector?

[Sebastian Schöps]

Montgomery-Smith, Stephen wrote
> My guess is that it is solving the underdetermined equation:
> 
> x1+x2+x3+x4=1.
> 
> So both solutions are correct answers.  There are infinitely many correct
> answers.
> 
> If I had to choose, I guess I would go for the answer who square sum is
> minimized, which would favor Octave's answer.

Thanks! That explains the behaviour and I agree that both solutions do make
sense. However, is that documented somewhere? Shouldn't there be a warning?
Similar to the case when a singular linear equation system is solved?

Sebastian



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