Il 11/Ott/2015 12:04, "Sebastian Schoeps" <address@hidden> ha scritto:
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> I think, we just need to call dense output as already implemented by Jacopo?!
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> Sebastian
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I guess Carlo's point is that Matlab by default returns the automatic timesteps used (and we do the same) but if one requires specific times then it only returns those ones in the output.
What we do in Octave is returning those timesteps together with the automatic ones (ie one would probably get 458 st in the example below). That was what I understood reading Matlab's documentation...
However it shouldn't be that complicated to change in the code isn't it? I guess it's just a change in the handling of the outputs...