|Subject:||failed to start (exit status -1) -- Program /usr/bin/php timed out|
|Date:||Thu, 4 Nov 2021 11:35:58 +0400|
I have a bit of trouble configuring a monitor and would appreciate your help.
It’s for a php job that runs forever and process a queue, I’ve setup monit like this:
check process QueuesProcessing
matching "/usr/bin/php /data/symfony/bin/console PosBundle:ProcessIncoming --env=prod"
start program = "/usr/bin/php /data/symfony/bin/console PosBundle:ProcessIncoming --env=prod"
as uid www-data and gid www-data
if does not exist then start
It seems it fails to start the command but I’m not sure why:
root@BATCH01:/etc/monit/conf.d# monit validate
'SERVER.VISION_QueuesProcessing' process is not running
'SERVER.VISION_QueuesProcessing' start: /usr/bin/php
'SERVER.VISION_QueuesProcessing' failed to start (exit status -1) -- Program /usr/bin/php timed out
I Googled this but couldn’t find something that speaks to me.
Would you know why I get a timeout calling php?
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