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Re: variable and tie
From: |
David Kastrup |
Subject: |
Re: variable and tie |
Date: |
Wed, 09 May 2018 13:05:37 +0200 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/26.0.50 (gnu/linux) |
Gianmaria Lari <address@hidden> writes:
> On 9 May 2018 at 10:45, David Kastrup <address@hidden> wrote:
>
>> Gianmaria Lari <address@hidden> writes:
>>
>> > On 13 April 2018 at 09:13, David Kastrup <address@hidden> wrote:
>> >
>> >> Gianmaria Lari <address@hidden> writes:
>> >> >
>> >> > At the moment I do this
>> >> >
>> >> > \version "2.19.81"
>> >> > var = {a b \tag #'lastnote a}
>> >> > {\removeWithTag #'lastnote \var a ~ a}
>> >> >
>> >> > but I would like to know if there are other solution (maybe better?).
>> >>
>> >> 2.21.0 (current master) ac"cepts it as-is.
>> >>
>> >> --
>> >> David Kastrup
>> >>
>> >
>> > What about this David:
>> >
>> > \version "2.19.81"
>> > var = {a b c d}
>> > {\var( \var )}
>> >
>> >
>> > Will it work in the future?
[image equivalent to { a b c d( a b c d) }
>> Probably not what you had in mind. ( and ) are not treated differently:
>> they are attached to the last note of a preceding phrase, similarly any
>> other post-event. But you could probably write
>>
>> {<>( \var \var )}
>>
>> instead to get what I presume to be the desired effect.
[which would be equivalent to { a( b c d a b c d) }]
> hihi :)
>
> This is exactly what I wanted. But I don't understand why your code works
> and mine doesn't.
> Isn't "var" a phrase and 'd' the last note of the that phrase?
This sounds like a misunderstanding. At least it does not make sense to
me.
--
David Kastrup