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| From: | lemzwerg |
| Subject: | Re: Only print out open type font substitution if there was a change (issue 577390043 by address@hidden) |
| Date: | Fri, 24 Jan 2020 09:37:42 -0800 |
Grammar nit.
https://codereview.appspot.com/577390043/diff/573430045/lily/open-type-font.cc
File lily/open-type-font.cc (right):
https://codereview.appspot.com/577390043/diff/573430045/lily/open-type-font.cc#newcode238
lily/open-type-font.cc:238: debug_output (_f ("Replace font name from %s
to %s.",
Is this correct English? Shouldn't this be rather
Replace font name '%s' with '%s'.
?
https://codereview.appspot.com/577390043/
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