
From:  estefaniame 
Subject:  Re: AR model 
Date:  Mon, 6 Jul 2020 15:46:39 +0200 
On Sunday, 5 July 2020 20.39.23 WEST estefaniame@gmail.com wrote:
> Thank you! I just want to calculate the roots of the associated polynomial
> to an autoregressive model. If I put [b2 b1 b0], wouldn't it be
> b2*x^2+b*x+b0?, as Octave represents polynomials from highest to lowest
> degree.
>
> Can you help me?
>
> Best,
>
> Estefanía
Yes
roots([b2 b1 b0])
is what you are looking for.
For those who could be confused with this consider a stationary time series, then Y_t=Y_(t1) and so on, that is why it is stationary. :)

José Matos
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