RE: ayuda

[Martin Helm]

Am Samstag, den 15.10.2011, 20:18 -0500 schrieb rolando rios cruz: 
> 
> 
> > Subject: Re: ayuda
> > From: address@hidden
> > To: address@hidden
> > CC: address@hidden
> > Date: Sun, 16 Oct 2011 02:47:51 +0200
> > 
> > Am Samstag, den 15.10.2011, 19:36 -0500 schrieb rolando rios cruz: 
> > > Hello I would like to calculate the number of days to a date to
> > > another, I tried to use functions like "date". I hope answer
> thanks 
> > > _
> > Something like that?
> > 
> > datenum(2011, 11, 2) - datenum(2010, 12, 31)
> > ans = 306
> > 
> > datenum(2011, 11, 2) - datenum(2011, 11, 1)
> > ans = 1
> > 
> > 
> 
> 
> 
> 
> 
> Thank, 
> but if I want to enter the date using the "input" function to add a
> date which would be the syntax?

Please keep the list on cc.

I guess you want something like this (just an example, you can use other
formats or calculate the difference to floor(now) which is just today)

dts = input ("Enter date as yyyy-mm-dd: ", "s");
dt1 = datevec(dts, "yyyy-mm-dd");
dts = input ("Enter a second date as yyyy-mm-dd: ", "s");
dt2 = datevec(dts, "yyyy-mm-dd");
difference = datenum(dt2) - datenum(dt1)