On Tue, Jun 30, 2009 at 4:37 PM, josgau33 <address@hidden>
wrote:
Hello all,
I'm trying to write a program I can use to load a large number of
data files
into Octave. The files all have the same naming convention:
Res2006001
...
Res2006365
Does anyone know if this can be done with an M-file? If so, could
you give
me some pointers. Thanks,
Joseph
Without knowing the details of the file types or the numbering
scheme it's hard to say. If the filenames are sequentially numbered
you could do something like this.
First, if the files aren't some standard file handled by octave or
the io or misc packages, the first step I recommend writing a
function that takes a file name and returns the data from that one
file. Let's call that load_my_data(). Then
data = load_my_data("Res2006001") ;
would read the file into data.
Now, to load many of them one approach is to generate filenames
using sprintf and store the data in a cell array. Suppose you have
500 files named like "Res2006001" to "Res2006501". Something like
this should get you started:
for i=1:500
name = sprintf("Res2006%03d", i) ;
data{i} = load_my_data(name) ;
endfor
One thing to be careful of is to make sure that you store data into
the cell starting at 1.
If it's difficult to generate the filenames, another option is to
store the filenames into a cell array and the load the data using
names from the cell array:
filenames = {"Res2006001","Res2006002", ................. ,
"Res2006501"};
for i=1:length(filenames)
data{i} = load_my_data(filenames{i}) ;
endfor