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Re: Structure items as vectors?
From: |
Sergei Steshenko |
Subject: |
Re: Structure items as vectors? |
Date: |
Mon, 14 Apr 2008 07:36:31 -0700 (PDT) |
--- David Bateman <address@hidden> wrote:
> Schirmacher, Rolf wrote:
> > Hello,
> >
> > I want to use structured information for numerical computations. I have a
> > structure like
> >
> > octave.exe> some.data.structure(1).item = 1;
> > octave.exe> some.data.structure(2).item = 2;
> >
> > and later on, I want to do calculations with a vector of "item"s. What I get
> > is a list like
> >
> > octave.exe> some.data.structure.item
> > ans =
> >
> > (,
> > [1] = 1
> > [2] = 2
> > ,)
> >
> > octave.exe> some.data.structure(:).item
> > ans =
> >
> > (,
> > [1] = 1
> > [2] = 2
> > ,)
> >
> >
> > On the other hand, I can access the individual elements as scalars like
> >
> > octave.exe> some.data.structure(1).item
> > ans = 1
> >
> >
> > How can I retrive the data as a vector, i.e. overcome such errors most
> > easily?
> >
> > octave.exe> items_doubled = 2 .* some.data.structure(:).item
> > error: binary operator `.*' not implemented for `scalar' by `cs-list'
> > operations
> > error: evaluating binary operator `.*' near line 59, column 19
> > error: evaluating assignment expression near line 59, column 15
> >
> >
>
> The returned value above is a comma-separated list in exactly the same
> manner as Matlab returns the above. Try "[some.data.structure.item]",
> which converts your comma seperated list into a matrix. Or if you can't
> be sure the data is numeric, try "{some.data.structure.item}" which
> converts it to a cell array.
>
> D.
>
>
>
>
>
> --
> David Bateman address@hidden
> Motorola Labs - Paris +33 1 69 35 48 04 (Ph)
> Parc Les Algorithmes, Commune de St Aubin +33 6 72 01 06 33 (Mob)
> 91193 Gif-Sur-Yvette FRANCE +33 1 69 35 77 01 (Fax)
>
> The information contained in this communication has been classified as:
>
> [x] General Business Information
> [ ] Motorola Internal Use Only
> [ ] Motorola Confidential Proprietary
>
> _______________________________________________
> Help-octave mailing list
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>
There is a couple of useful functions allowing to know for sure what kind of
object it is, namely
'class', 'ismatrix'.
Here is an example:
"
help class
octave:1> help class
-- Built-in Function: class (EXPR)
Return the class of the expression EXPR, as a string.
class is a built-in function
Additional help for built-in functions and operators is
available in the on-line version of the manual. Use the command
`doc <topic>' to search the manual index.
Help and information about Octave is also available on the WWW
at http://www.octave.org and via the address@hidden
mailing list.
octave:2> a.b.c.d =1
a =
{
b =
{
c =
{
d: 1x1 scalar
}
}
}
octave:3> class(a)
ans = struct
octave:4> a.b.c.e = [1,2,3]
a =
{
b =
{
c =
{
d: 1x1 scalar
e: 1x3 matrix
}
}
}
octave:5> class(a.b.c.e)
ans = double
octave:6> ismatrix(a.b.c.e)
ans = 1
octave:7> a.b.c.f{2} = [10,20,30]
a =
{
b =
{
c =
{
d: 1x1 scalar
e: 1x3 matrix
f: 1x2 cell
}
}
}
octave:8> a.b.c.f{3} = [40,50]
a =
{
b =
{
c =
{
d: 1x1 scalar
e: 1x3 matrix
f: 1x3 cell
}
}
}
octave:9> class(a.b.c.f)
ans = cell
octave:10> class("hello")
ans = char
octave:11>
".
Regards,
Sergei.
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