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Re: How to average to find 'circular' symmetry in a SQUARE matrix?
From: |
Robert A. Macy |
Subject: |
Re: How to average to find 'circular' symmetry in a SQUARE matrix? |
Date: |
Mon, 15 Jan 2007 17:31:51 -0800 |
Doug,
Yes, 1 degree, 10 degrees, or 127 degrees, image that is
represented by x-y data set is perfectly axisymmetric.
How do I use polar notation to average?
- Robert -
Chris,
How do I use 2D Lagrange interpolation? Sounds exactly
what I need, but didn't find any functions that looked like
it would do that.
What were you using it on?
- Robert -
From: "Chris Zarowski" <address@hidden>
> Maybe I misunderstand, but it sounds like
> you need to do interpolation in 2D.
>
> There is a 2D form of Lagrange interpolation
> that is perhaps the easiest thing.
>
> The idea is to interpolate over a desired circle
> (appropriately centered), and average the interpolants.
>
> I actually had this problem in processing some
> grey-scale images from a thin-film optics experiment.
>
> Chris Z
On Mon, 15 Jan 2007 19:06:24 -0500
Doug Stewart <address@hidden> wrote:
> Hi Robert
>
> Do you mean by rotational symmetry that if you rotate
> it 10 deg ( or
> 20 or 30 etc.) it still has symmetry or do you mean
> rotate by 90 deg. steps.
>
>
> If it is by any deg. then maybe you could use polar
> notation?
>
> Doug Stewart