Re: define range in octave

[Aarti Gupta]

I am trying to construct a histogram for a given data set. And I want my
bucket ranges as (0-5), (5-15), (15-25),(25-35),(35-45)
and since, there are not continous that after 5 I want 15 how can I do this
in octave?
Even I not able to get the marks for this in the x-axis.
How can I get the marks for this in the axes?
----- Original Message -----
From: "Jordi Gutierrez Hermoso" <address@hidden>
To: "Aarti Gupta" <address@hidden>
Cc: <address@hidden>
Sent: Tuesday, July 25, 2006 5:22 PM
Subject: Re: define range in octave


> Hi.
>
> On 25/07/06, Aarti Gupta <address@hidden> wrote:
> > I want range as (0-5), (5-15), (15-25),(25-35), (35-45)
>
> I don't quite understand what you want. The colon operator will define
> a range for you, so that, e.g.
>
> octave:1> x = 1:10
> x =
>
>    1   2   3   4   5   6   7   8   9  10
>
> and you can specify a different step size, but the default is 1:
>
> octave:2> x = 1:pi/2:10
> x =
>
>    1.0000   2.5708   4.1416   5.7124   7.2832   8.8540
>
> Those are five different ranges you have there. The first one could be
> x=0:5, the next y = 5:15, and so on. What's the context? What are you
> trying to do?
>
> - Jordi G. H.