RE: Select elements according to the index

[Chen, Minyu]

This is only a problem with Octave 2.1.40. As I upgraded to Octave
2.1.64, it doesn't present any problem. So people with 2.1.64 need not
be disturbed by my post.

Thanks,
Minyu Chen



-----Original Message-----
From: Chen, Minyu [mailto:address@hidden 
Sent: 13 February 2005 13:32
To: address@hidden
Subject: Select elements according to the index



Hi:

Sorry if my question seems too simple.

Suppose I have an index matrix of 2 by 3, e.g. a=[1 2 3; 4 5 6]

And have a vector of 1 by 8, e.g. b=[.1 .2 .3 .4 .5 .6 .7 .8]

And I want to create a matrix c of 2 by 3 (the same dimension of a),
with c(i,j)=b(a(i,j)), that's being said:

c=[.1 .2 .3; .4 .5 .6]

In matlab, as memory serves correctly, I can do it by typing:

c=b(a)

but this command in Octave will generate only a vector of 1 by 6:

c=[.1 .4 .2 .5 .3 .6]

How can I get the matrix I want?

Many Thanks,
Minyu Chen



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Octave is freely available under the terms of the GNU GPL.

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