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Re: An other problem
From: |
Yann Lamontagne a.k.a. daume |
Subject: |
Re: An other problem |
Date: |
Fri, 20 Jun 2003 12:08:02 +0000 (UTC) |
Maybe it was the initial condition since I know I have the right formula
from http://astronomy.swin.edu.au/%7Epbourke/fractals/lorenz/ and a text
book. But the now with the same way to write the equation(not same
formula) and your initial condition I get nice results.
thanks
YAnn
On Thu, 19 Jun 2003, John W. Eaton wrote:
> Date: Thu, 19 Jun 2003 23:17:34 -0500
> From: John W. Eaton <address@hidden>
> To: Yann Lamontagne a.k.a. daume <address@hidden>
> Cc: help-octave mailing list <address@hidden>
> Subject: An other problem
>
> On 20-Jun-2003, Yann Lamontagne a.k.a. daume <address@hidden> wrote:
>
> | I am trying to plot
> | function xdot = lorenz(x)
> | xdot(1) = 10*x(2) - 10*x(1)
> | xdot(2) = x(1)*2.666 - x(3)*x(1) - x(2)
> | xdot(3) = x(1)*x(2) - 28*x(3)
> | end
> | solution=lsode( "lorenz",[1, 1, 1], t = linspace(0.0,100, 5000))
> | gset parametric
> | gsplot(solution)
> |
> | the solution seems to have two sets of data and I believe it is plotting
> | the wrong set, do anyone know how to fix that?
>
> I think you are doing the right thing, but the set of equations that
> you are using don't look like the same ones I have seen before. Also,
> starting point is critical to getting a interesting behavior and a
> pretty plot. If I use
>
> function y = lorenz (x, t)
> y = [10 * (x(2) - x(1));
> x(1) * (28 - x(3));
> x(1) * x(2) - 8/3 * x(3)];
> endfunction
> x = lsode ("lorenz", [3; 15; 1], (0:0.01:25)');
> gset parametric
> gsplot x
>
> I get a plot that looks a lot like the one on the Octave home page
> (but with 3d axes).
>
> jwe
>
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