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tmp=0; tmp+1:(tmp+=5)

From: Etienne Grossmann
Subject: tmp=0; tmp+1:(tmp+=5)
Date: Sat, 21 Jul 2001 11:05:17 +0100
User-agent: WEMI/1.13.7 (Shimada) FLIM/1.13.2 (Kasanui) Emacs/20.7 (i386-debian-linux-gnu) (with unibyte mode)


  I would like to know whether the in a range "a:b", the left operand
is always evaluated before the second. That is, can I do :

  tmp=0; tmp+1:(tmp+=5)

  and expect to get 1:5. I didn't find where in the docs the order of
evaluation is specified.

  With 2.1.34, this works. Is it an undocumented feature? Can I expect
it to work w/ future versions?



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