Re: eigenvectors

[Daniel Heiserer]

address@hidden wrote:
> 
> address@hidden wrote:
> >
> > This may be a dumb question, forgive me, it's been too long.
> >
> > I have a real, square matrix Q and I need to factorize it as
> >
> >         Q = inv(X)*D*X
> >
> > where D is diagonal.  I think that this means that D contains the
> > eigenvalues and X contains the eigenvectors of Q.  Is that right?  How do
> > I get D and X from octave.  The function svd gives the "right and left"
> > eigenvectors for any matrix.  I thought that for square matrices this
> > would mean that it would return X but I was wrong.
> >
> > Sheepishly,
> > Heber
> >
> >
> 
> Well, the problem is that not every matrix can be factorized in that
> way. In general, what one has is the _Jordan_ form.  Furthermore, the
> singular value decomposition (svd) is not directly related to your
> problem. The situation is difficult to explain in just few lines, you
> may want to consult a linear algebra textbook on the matter.
> 

Yeah. Is there a [J,X]=jordan(X) function in octave, or can somebody
contribute one?

Bye daniel

-- 
Mit freundlichen Gruessen
                                 Daniel Heiserer
-----
--------------------------------------------------------------
Dipl.-Phys. Daniel Heiserer, BMW AG, Knorrstrasse 147, 80788 Muenchen
Abteilung EK-20
Tel.: 089-382-21187, Fax.: 089-382-42820
mailto:address@hidden



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