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## Re: [Help-gsl] dawsons integral for imaginary arguments

**From**: |
Brian Gough |

**Subject**: |
Re: [Help-gsl] dawsons integral for imaginary arguments |

**Date**: |
Thu, 13 Apr 2006 14:38:06 +0100 |

Carsten Fortmann writes:
>* I need the following expression*
>* *
>* exp(x*x)erfc(x) (1).*
>* *
>* Due to the exp(x*x) (not exp(-x*x)!!!),*
>* this expression returns a nan for large arguments. I found out, that *
>* (1) is in principal given by dawsons integral for purely imaginary *
>* argument. Does anyone know how to obtain this in gsl?*
Hello,
Apart from constant factors it is 1/gsl_sf_hazard().
See http://www.network-theory.co.uk/docs/gslref/gsl-ref_105.html
--
Brian Gough
Network Theory Ltd,
Publishing the GSL Manual - http://www.network-theory.co.uk/gsl/manual/